What are the roots of the polynomial equation x^3-7x=6x-12?
a. –6, 6
b. –4, 1, 3
c. –3, –1, 4
d. 1, 3

Hello,

Answer B

P(x)=x^3-13x+12
P(1)=1-13+12=0 ==>1 is root
P(3)=3^3-13*3+12=0 ==>3 is root
P(-4)=(-4)^3-13*(-4)+12=0 is root

P(x)=(x-1)(x-3)(x+4)

Intinisbinidbifbisbe

Don’t know sorry about that