Lebron needs 150 milliliters of a 30% solution of sulfuric acid for a lab experiment but only has access to a 25% and a 50% solution. how much of the 25% and how much of the 50% solution should he mix to make the 30% solution?

Step-by-step explanation:

Let x represent the amount of 50% solution LeBron needs. Then (150-x) is the amount of 25% solution, and the total amount of acid in the mix is ...

  50%(x) +25%(150 -x) = 30%(150)

  .25x + 37.5 = 45 . . . . . simplify

  .25x = 7.5 . . . . . . . . . . . subtract 37.5

  x = 7.5/.25 = 30 . . . .  divide by the coefficient of x; mL of 50% solution

  150-x = 120 . . . . . . . . mL of 25% solution

LeBron should mix 120 mL of 25% solution with 30 mL of 50% solution to make the 30% solution.

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6