An airliner flies against the wind on one leg of its round trip in 6.5 hours. it flies back to it's starting point, with the wind in 6 hours. if the average speed of the wind is 20 miles per hour, what is the speed of the airliner in still air?

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step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

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yes because they have the same amount of green and blur marbles.

step-by-step explanation:

25.3

step-by-step explanation:

1st step

add 3+6

=9

multipy 9*3

=37