Find the greatest common factor of these three expressions. 18y4, 30y3, and 42y5

6y³

Step-by-step explanation:

All three numbers are divisible by 6 and by y³

Leaving you with 3y, 5, and 7y²

2nd one in the first row is correct

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.