The round off error when measuring the distance that a long jumper has jumped is uniformly distributed between 0 and 5 mm. round all answers to two decimal places. a. the mean of this distribution is b. the standard deviation c. the probability that the round off error for a jumper's distance is exactly 2.5 mm is p(x = 2.5) = d. the probability that the round off error for the distance that a long jumper has jumped is between 2 and 4 mm is p(2 < x < 4) = e. the probability that the jump's roundoff error is greater than 1 is p(x > 1) = f. p(x > 4 | x > 2) = = probability that x is greater than 4, given that it is greater than 2 = g. find the 60th percentile. h. find the minimum for the upper quartile.

Solution to all the parts are shown below.            

Step-by-step explanation:

We are given the following information in the question:

The distance of a long jumper is uniformly distributed between 0 and 5 mm.

Probability Distribution:

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

step-by-step explanation:

my butt