Amodel rocket is launched with an initial upward velocity of 47 ms. the rocket's height (in meters) after seconds is given by the following. find all values of for which the rocket's height is 27 meters. h=47t-5y^2

0.61 or 8.79

Step-by-step explanation:

h = 47t − 5t²

27 = 47t − 5t²

5t² − 47t + 27 = 0

Quadratic formula:

t = [ -b ± √(b² − 4ac) ] / 2a

t = [ -(-47) ± √((-47)² − 4(5)(27)) ] / 2(5)

t = (47 ± √1669) / 10

t ≈ 0.61 or 8.79

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.