The mass of a penny was measured six times. the following data was reported:
9.314 g, 9.215 g, 9.323 8 8.103 g, 9.278 g, and 9.344 g. 5.

(a) should any data be excluded in calculating the average mass of the penny?
(b) calculate the average value of the mass of the penny, excluding unreasonable value
(c) calculate the average deviation from the mean.

a) 8.103 g

b) 9.2948

c) 0

Step-by-step explanation:

Given:

Data reported:

9.314 g, 9.215 g, 9.323 g, 8.103 g, 9.278 g, and 9.344 g

Now,

All the values except the 8.103 are above 9

Here the data 8.103 varies very much with respect to the other values

Hence,

a) the data 8.103 should be excluded

b) average value of the mass of the penny =

= 9.2948 g

c) Deviation = Mean - Data

9.2948 - 9.314 = -0.0192

9.2948 - 9.215 = 0.0798

9.2948 - 9.323 = -0.0282

9.2948 - 9.278 = 0.0168

9.2948 - 9.344 = -0.0492

Thus,

Average deviation from mean = tex]\frac{-0.0192 + 0.0798 -0.0282 + 0.0168 -0.0492 }{5}[/tex]

= 0

answer: the answer is b. i think hope i got it correct

step-by-step explanation:

step-by-step explanation: