Two different airlines have a flight from los angeles to new york that departs each weekday morning at a certain time. suppose that e denotes the event that the first airline's flight is fully booked on a particular day, and f denotes the event that the second airline's flight is fully booked on that same day. suppose that p(e) = 0.7, p(f) = 0.6, and p(e ∩ f) = 0.49. calculate p(e | f) the probability that the first airline's flight is fully booked given that the second airline's flight is fully booked.

0.8167

Step-by-step explanation:

Let E denotes the event that the first airline's flight is fully booked on a particular day, and F denotes the event that the second airline's flight is fully booked on that same day.

Given :  P(E) = 0.7, P(F) = 0.6, and P(E ∩ F) = 0.49.

Then,  by conditional probability formula , we have

Hence, the probability that the first airline's flight is fully booked given that the second airline's flight is fully booked.= 0.8167

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

throw the computer

step-by-step explanation: