Miley and cole ended up making the same number of biscuits for a bake sale at school, even though miley made them in batches of 7 biscuits and cole made them in batches of 11 biscuits . what is the smallest number of biscuits each must have baked?

Step-by-step explanation:

For this exercise you need to find the Least Common Multiple (LCM).

The steps two find the Least Common Multiple are shown below:

1. Descompose the numbers into their prime factors.

2. Multiply the commons an non commons with the highest exponent. The product obtained will be the Least Common Multiple.

Knowing this, you can find the Least Common Multiple between 7 and 11. This is:

Therefore the smallest number of biscuits each must have baked is:  

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺