We say that a real numberx∈[0,1) is computable if there exists an algorithm which, given〈n〉as input for an arbitrary natural numbern, computes (in a finite number of steps) thenth (binary) digit ofxafter the decimal point. this means that a computable number canbe approximated to any desired degree of precision. prove that there exist uncountably manyuncomputable numbers

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

but which class are u may know that first

answer: (-6,3)

step-by-step explanation: