An observation deck extends 314 feet out above a valley. the deck sits 264 feet above the valley floor. if an object is dropped from the observation deck, its height h in feet, after t seconds, is given by h equals negative 16 t squared plus 264. how long will it take for the object to be 8 feet above the valley floor?

4.12 s

Step-by-step explanation:

The equation given in the question that relates the height (h), and the time (t) is:

h = -16t² + 264

So, for h = 8 ft

8 = -16t² + 264

16t² = 264 + 8

16t² = 272

t² = 17

t = √17

Which can be approximadelly to 4.12 s

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

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30005

yes ok