Mathematics, 18.10.2019 18:00 Zaida21
Now that you have worked with divide and conquer algorithms and recurrences, we will try to combine it all together. in a divide and conquer algorithm, the problem is divided into smaller subproblems, each subproblem is solved recursively, and a combine algorithm is used to solve the original problem. assume that there are a subproblems, each of size 1/b of the original problem, and that the algorithm used to combine the solutions of the subproblems runs in time cnk, for some constants a, b, c, and k. for simplicity, we will assume, n=bm, so that n/b is always an integer (b is an integer greater than 1). answer the following: (a) write the generalized recurrence equation. (b) solve the recurrence equation using a recursion tree approach. base case, t(1) = c.
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Mathematics, 21.06.2019 17:20
If you are just building your payment history, how many points from a perfect score will you possibly miss?
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Mathematics, 21.06.2019 22:00
Problem situation: caren is making rice and beans. she can spend no more than $10 on ingredients. she buys one bag of rice for $4.99. beans cost $0.74 per pound. how many pounds of beans, x, can she buy? inequality that represents this situation: 10≥4.99+0.74x drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution.
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Mathematics, 22.06.2019 01:30
Asample of 200 rom computer chips was selected on each of 30 consecutive days, and the number of nonconforming chips on each day was as follows: the data has been given so that it can be copied into r as a vector. non.conforming = c(10, 15, 21, 19, 34, 16, 5, 24, 8, 21, 32, 14, 14, 19, 18, 20, 12, 23, 10, 19, 20, 18, 13, 26, 33, 14, 12, 21, 12, 27) #construct a p chart by using the following code. you will need to enter your values for pbar, lcl and ucl. pbar = lcl = ucl = plot(non.conforming/200, ylim = c(0,.5)) abline(h = pbar, lty = 2) abline(h = lcl, lty = 3) abline(h = ucl, lty = 3)
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Now that you have worked with divide and conquer algorithms and recurrences, we will try to combine...
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