Box a contained only 50-cent coins while box b contained only 20 cents coins. box b has 60 more coins than box a but the value of all the coins in box a is $4.50 more than the value of all the coins in box b. find the amount of money in box a.

x numbers of coins in box A = 55

y numbers of coins in box B = 115

Step-by-step explanation:

the numbers of coins in box  y = x + 60

the value in cent of $ in box A is 50*x

and the value in cent of $ in box B is 20*y

So     50*x = 20*y +450

             y = 60 + x

Solving for x              50x = 20*(60+x) +450      50x = 1200 + 20x +450

                                        30x = 1650      x = 55

             y = 60 +55 =115