Arectangle has perimeter 72 cm and length of 31 cm. what is its width?

the width of the rectangle is 5

Step-by-step explanation:

because if the perimeter is 72 and the length is 31, 31 + 31 = 62 right? so then if you subtract 62 from 72 then you would get 10 right? so what is half of 10? 5 so the width of the rectangle is 5 because you have to add all the numbers together. 31 + 31 = 62 and 5 + 5 = 10 and 10 + 62 = 72 the perimeter!

Width: 5

Step-by-step explanation:

Perimeter is found by adding all the sides together.

1. Multiply 31 by 2 so that you get the total length of both sides.

2. 31 x 2 = 62

3. Subtract 62 from 72 in order to get the total width of both sides.

4. 72 - 62 = 10

5. Divide 10 by 2 to get the width of one side.

6. 10 / 2 = 5

5 is your width.

the cat is blue because the probability of extension towards the prefix of the diameter of the circle could only mathematically equal to the sum of the roots of the carrots from   your garden.

step-by-step explanation:

are ya tryin to ask something or is this a statement