One institute mandates that for every 100 items scanned through the electronic checkout scanner at a retail store, no more than 2 should have an inaccurate price. a recent study of the accuracy of checkout scanners at the stores of a certain company showed that, of the 70 company stores investigated, 56 violated the institute's scanner accuracy standard. if 1 of the 70 company stores is randomly selected, what is the probability that that store does not violate the institute scanner accuracy standard?

There is a 20% probability that the store selected does not violate the institute scanner accuracy standard

Step-by-step explanation:

70 company stores were investigared.

56 violated the institute's scanner accuracy standard.

70-56 = 14 did not violate the institute scanner accuracy standard.

If 1 of the 70 company stores is randomly selected, what is the probability that that store does not violate the institute scanner accuracy standard?

This is 14 divided by 70, so:

There is a 20% probability that the store selected does not violate the institute scanner accuracy standard

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.