10 cards are numbered from 1 to 10 and placed in a box. one card is selected at random and is not replaced. another card is then randomly selected. what is the probability of selecting two prime numbers?

Step-by-step explanation:

The prime numbers between 1 and 10 are;

1, 2, 3, 5, 7

The probability of drawing the first card =

Since there is no replacement, the probability of drawing the second card =

The probability of selecting two prime numbers between 1 and 10 without replacement = × =

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb

the equation is not included but the answer is (1.50, 2.00, 2.75)

step-by-step explanation: