Acolor photograph taken with a digital camera is converted into digital format using 4\cdot10^04⋅10 0 4, dot, 10, start superscript, 0, end superscript bytes per pixel. photographs taken with the camera each have 2.2\cdot10^62.2⋅10 6 2, point, 2, dot, 10, start superscript, 6, end superscript pixels. how many bytes are there in one photo?

bn,mn,n.vn.

step-by-step explanation:

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation:

18 units²

step-by-step explanation:

first let's find altitude bd using the distance formula

d = √((y₂ - y₁)² + (x₂ - x₁)²)

bd = √((0 - -3)² + (0 - 3)²)

bd = √18

given the placement of points a and c, we can denote that point d bisects segment ac.

we will call ac the base.

using the distance formula

ac = √((0 - 6)² + (-6 - 0)²)

ac = √72

knowing our base and our height, we can plug these into our triangle area formula

area = (b * h)/2

area = (√18 * √72) / 2

area = (√1296) / 2

area = 36 / 2

area = 18 units²

um is there supposed to be a picture?