The random variable x, representing the number of items sold in a week, has the following probability distribution: x 0 1 2 3 4 5 6 p(x = x) 0.10 0.20 0.40 0.15 0.05 0.05 0.05 by the fourth day of a particular week, 3 items have already sold. what is the probability that there will be less than a total of 5 items sold during that week?

0.667

Step-by-step explanation:

Data provided:

x                0                1              2              3              4              5              6

P(X = x)    0.10         0.20         0.40         0.15         0.05         0.05         0.05

Now,

The probability that less than 5 items will be sold in a week given that 3 items have already been sold can be calculated as;

P ( less than 5 items sold | 3 or more items sold )

=

=

or

P ( less than 5 items sold | 3 or more items sold ) =

or

P ( less than 5 items sold | 3 or more items sold ) =

or

P ( less than 5 items sold | 3 or more items sold ) = 0.667

3. (5x + 1) - (-10x + 6)

simplify the answer choice. combine like terms. remember to distribute the negative to the terms inside the second parenthesis. also remember that two negatives = one positive, and one of each sign = negative.

- (-10x + 6) = + 10x - 6

simplify. combine like terms:

5x + 1 + 10x - 6

5x + 10x + 1 - 6

15x - 5

∴ it is your answer

~

mnkjn

step-by-step explanation: