Let p=(x, y) be a point on the graph of y= 1/x. express the distanced from p to the point x (2,0) as a function of x. what is d if x=2?

D = SQRT (x^4 + 17x^2 + 64)    This is the distance as a function of x

Step-by-step explanation:

This problem uses the Pythagorean Theorem to determine the length of a hypotenuse of a right triangle.

The base of the triangle goes x distance along the x-axis, then y distance up to the point in question.  What is the distance (the hypotenuse of that triangle) as a function of x?

D = SQRT (x^2 + y^2)

D = SQRT (x^2 + (x^2+8)^2)         (substitute for y)

D = SQRT (x^2 + x^4 + 16x^2 + 64)        (expand using FOIL)

D = SQRT (x^4 + 17x^2 + 64)                (revise order, collect terms)

   This is the distance as a function of x

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation:

geometry: triangles

solvers

lessons

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call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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