Focus groups of 11 people are randomly selected to discuss products of the famous company. it is determined that the mean number (per group) who recognize the famous brand name is 6.2, and the standard deviation is 0.51. would it be unusual to randomly select 11 people and find that greater than 9 recognize the famous brand name?

It would not be unusual to randomly select 11 people and find that greater than 9 recognize the famous brand name.

Step-by-step explanation:

Since we have given that

Mean = 6.2

Standard deviation = 0.51

Average number of people  = 11

So, using the normal distribution, we get that

Now, we will check that

Hence, It would not be unusual to randomly select 11 people and find that greater than 9 recognize the famous brand name.

v v cj van config k tbs eng r.c r.c fcb fb gb frfr

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3