Perpendicular to the line y=1/2x-8; passes through (7,-6). write the slope-intercept form of the equation.

ANSWER:

The slope intercept form of the required line is y = -2x + 20.

SOLUTION:

Given, line equation is

And, Perpendicular line to the given line  passes through (7,-6).  

We need to find the slope intercept form of perpendicular line of given line.  

We already have the point (7, -6) but we need to find the slope.

Now, we know that, product of slopes of two perpendicular lines equals to -1.

Slope of given line is , by comparing with the general form of slope intercept form.

slope of required line = -1

Slope of perpendicular line = -2

Now, line equation of perpendicular line in point slope form is

y – (-6) = -2(x – 7)

y + 6 = -2x + 14

y = -2x + 20

the above equation is in the form of slope intercept form of a line equation  

where slope m = -2 and intercept c = 20

hence, the slope intercept form of the required line is y = -2x + 20.

i think the answer is .36

step-by-step explanation:

what i did was only 2.88 divided by 8

the value of v.w= -12.

step-by-step explanation:

we are given three vector r,v and w as:

r = < 5, -5, -2> ; v = < 2, -8, -8> ; w = < -2, 6, -5>

we know that r,v and w could also be represented as:

r=5i-5j-2k

v=2i-8j-8k

and w= -2i+6j-5k

where i,j and k are the unit vectors of x,y and z-axis respectively.

also we know that it has the following property:

i.i=1 ; j.j=1; k.k=1

and i.=j.i=i.k=k.i=j.k=k.j=0

i.e. when we multiply two vectors or we find it's dot product we need to only multiply the components of x coordinates with each other; y with each other and z with each other.

hence, v.w= (2i-8j- -2i+6j-5k)

                  = 2×(-2)+(-8)×(6)+(-8)×(-5)

                  = -4-48+40

                  = -12

hence, v.w= -12