Determine the values of x, if any, at which the function is discontinuous. at each number where f is discontinuous, state the condition(s) for continuity that are violated. (select all that apply.)f(x) = |x − 1|the function f is discontinuous at x = 1 because f is not defined at x = 1.the function f is discontinuous at x = 1 because lim x → 1 f(x) does not exist. the function f is discontinuous at x = 1 because lim x → 1 f(x) exists, but this limit is not equal to f(1).the function f is continuous everywhere because the three conditions for continuity are satisfied for all values of x.

The function f is continuous everywhere because the three conditions for continuity are satisfied for all values of x.

Step-by-step explanation:

The definition of continuity of a function is:

A function f (x) is continuous at x = a if the following three conditions are met:

We check each condition when x=1

1) f(x)=|x-1| so f(1)=|1-1|=0

The value of f(x) exits when x=1

2) The limit as x approaches 1 of |x-1| can be checked with lateral limits:

=0

=0

Both limits have the same value to the limit exist when x approaches 1.

3) =0=f(1)

The limit as x approaches 1 of f(x) is equal to the value of f(x) exits when x=1

idk lol

step-by-step explanation: