Refer to exercise 4.27. a more detailed examination of the company records indicates that 95% of the customers who pay one monthly bill in full will also pay the next monthly bill in full; only 10% of those who pay less than the full amount one month will pay in full the next month. a. find the probability that a customer selected at random will pay two consecutive months in full. b. find the probability that a customer selected at random will pay neither of two consecutive months in full. c. find the probability that a customer chosen at random will pay exactly one month in full.

answer: re

step-by-step explanation: idk buddy

you are saying it as if a fact, not a question, but yes, you would be correct? ; )

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)

step-by-step explanation:

the answer is 89 d

i took the test