Find how many terms of a geometric progression 1+3+9 are required to make a total of more than 1 million.

The partial sum of a geometric sequence is

In your case a=3, so if we sum N terms of the sequence we have

We want this to me more than 1 million, so we have

Considering the log (base 3) of both sides, we have

So, starting from N=13, the sum of the first N terms will be more than 1 million

answer: no

step-by-step explanation:

you are only given the cost not the amount of pounds.