Aboat traveled 240 miles downstream, then 240 miles back up stream. the trip downstream took 20 hours. the trip back up stream took 60 hours.
the speed of the boat in still water is miles per hour.
the speed of the current is miles per hour.

The speed of the boat in still water is 2 miles per hour

The speed of the current is 4 miles per hour

The calculation can be one as follows

let a represent the speed of the boat

let b represent the speed of the current

20(a+b)= 240equation 1

60(a+b)equation 2

a + b= 12equation 3

a - b= 4equation 4

Add both equation 3 and 4 together

(a + b) + (a - b)= 12+4

2x = 16

a= 16/2

a= 8

Subtract equation 4 from equation 3

(a + b) - (a-b)= 12-4

2b= 8

b= 8/2

b= 4

Hence the speed of the boat is 2 miles per hour and the speed of the current is 4 miles per hour.

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The speed of the boat in still water is 8 miles per hour.

The speed of the current is 4 miles per hour.

Step-by-step explanation:

Let x mph be the speed of the boat in still water and y mph be the speed of the current.

A boat traveled 240 miles downstream, it took him 20 hours. Tavelling downstream, the current "helps" and the speed of the boat is x + y mph. Thus,

A boat traveled 240 miles upstream, it took him 60 hours. Tavelling downstream, the current "interferes" and the speed of the boat is x - y mph. Thus,

Solve the system of two equations:

Add these two equations:

Subtract these two equations:

horizontal translation of 2 units in the positive x direction

followed by

vertical translation of 3 units in the positive y direction

answer: i think one of the answer is $150 and $300?

step-by-step explanation: