One number is 9 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 1123, find the numbers

ANSWER:

One number is 9 times a first number. The numbers are 93, 837 and 193.

SOLUTION:

Given, one number is 9 times a first number.  

A third number is 100 more than the first number.

The sum of the three numbers is 1123,  

We need to find the numbers.

let the first second and third numbers be a, b, c respectively

According to given information, b = 9a (1)

c = 100 + a (2)

a + b + c = 1123 (3)

now substitute (1) and (2) in (3)

a + 9a + 100 + a = 1123

11a + 100 = 1123

11a = 1123 – 100

11a = 1023

a = 93

now substitute a value in (1) and (2)

b = 9 x 93 = 837

c = 100 + 93 = 193

hence, the numbers are 93, 837, 193.

answer: 5000

step-by-step explanation:

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19