Maria studied the traffic trends in india. she found that the number of cars on the road increases by 10% each year. if there were 80 million cars in year 1 of her study, how many more cars were on the road in year 3 compared to year 2?
8,000,000
8,800,000
88,000,000
96,800,000

Option B

ANSWER:

8800000 more cars were on the road in year 3 compared to year 2

SOLUTION:

Given, Maria studied the traffic trends in India.  

She found that the number of cars on the road increases by 10% each year.  

If there were 80 million cars in year 1 of her study, we need to find how many more cars were on road in year 3 compared to 2.

Cars on road in 1st year = 80,000,000

Now, according to maria study,

Cars on road in 2nd year = cars on road in 1st year + 10% x cars on road in 1st year

= 80000000 + 10% x 80000000

= 80000000 + 8000000

= 88000000

Hence cars on road in 2nd year = 88000000

Now, Cars on road in 3rd year = cars on road in 2nd year + 10% x cars on road in 2nd year

= 88000000 + 10% x 88000000

= 88000000 + 8800000

= 96800000

Hence cars on road in 3rd year = 96800000

Number of excess cars in 3rd compared to 2nd = cars on road in 3rd year - cars on road in 2nd year

= 96800000 – 88000000

= 8800000

So, there are 8800000 more cars in third year that second year.

Hence, the second option, 8800000 is right answer.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

i can

step-by-step explanation: