Twenty identical looking packets of white power are such that 15 contain cocaine and 5 do not. four packets were randomly selected, and the contents were tested and found to contain cocaine. two additional packets were selected from the remainder and sold by undercover police officers to a single buyer. what is the probability that the 6 packets randomly selected are such that the first 4 all contain cocaine and the 2 sold to the buyer do not?

The probability of selecting randomly 6 packets such that the first 4 contain cocaine and 2 not is 0.3522.

Step-by-step explanation:

Probabilities of selecting 4 packets with the ilegal substance:

=

Combinassions possible= 1365

Probabilities of selecting 2 packets with white powder:

=

Combinations possible= 10

Probabilities of selecting 6 packets from the totality of them:

=

Combinations possible= 38760

The probability of picking 4 with the substance and 2 with only white powder is:

= 0.3522

I hope this answer helps you.

answer: no

step-by-step explanation:

answer: a. 13/44

step-by-step explanation: judging by the information given to us, we are looking for experimental probability. we can see that 13 males have chosen chocolate ice cream. there are 44 ice creams in total (remember that the total is always the denominator). so our answer is 13/44.