Brainliest first correct !

if grace and claire’s parents each invested $7,600 into a college saving account when the girls were born, how much money will each girl have when she turns 18? explain.

So, if they had $7600 in their banks at birth, and they had 10000 in their banks when they were 3, what is a 2,400 increase. Divide that by 3 = 800.

They get $800 a year.

So, for 18 years, thats 800 * 18 = 14,400.

Add that to what they started with: 14,400 + 7,600 = 22,000.

Claire would have $22,000 when she turns 18.

Graces Money: y = 1000x + 7600

We can assume that y = how much should would have at the end of 18 years and x = the amount of money she gets per year.

So, it would by y = 1000(18) + 7600

1000 * 18 = 18000

18000 + 7600 = 25600

Grace would have $25,600 at the end of 18 years.

grace will have $25,600 when she is 18 and claire will have $22,000 when she is 18.

Step-by-step explanation:

since x is the age, for grace you can just plug in 18 for x

y = 1000(18) + 7600

y = 18000 + 7600

y = 25600

for claire you have to find out the slope, to do that you can do rise over run:

11600/5 - 10000/3 = 1600/2 = 800

so the formula for claire is y = 800x + 7600

and again, you can just plug in 18 for x

y = 800(18) + 7600

y = 14,400 + 7600

y = 22,000

36 is the final answer! : )

anser is a

step-by-step explanation:

negitive slope