Which point is in the solution set for y < x+2? explain your answer.

question 2 options:

(0, 2) because when you graph y < x+2, it is a point on the boundary line.

(1, 4) because when you graph y < x+2, it is a point that lies above the boundary line.

(2, 1) because when you graph y < x+2, it is a point that lies below the boundary line.

(-2, 0) because when you graph y < x+2, it is the x-intercept of the boundary line.

The table shows the distance traveled over time while traveling at a constant speed.

The step function g(x) is defined as shown.what is the range of g(x)? ***answer choices in picture.

Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane