Let x be the number of flaws on the surface of a randomly selected boiler of a certain type and suppose x is a poisson distributed random variable with parameter μ = 5. find p(2 ≤ x ≤ 4)

0.40006

Step-by-step explanation:

Let as assume that X is a Poisson distributed random variable with parameter μ = 5.

Poisson distribution Formula:

where, μ is mean.

We need to find the value of P(2 ≤ X ≤ 4).

Therefore the value of P(2 ≤ X ≤ 4) is 0.40006.

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.