How many integers between 160 and 279 inclusive, are divisible by 7?

17

Step-by-step explanation:

We can put this as an AP (arithmetic progression).

The first number, after 160, that is divisible by 7 is:

161

The last number before 279 that is divisible by 7 is:

273

We can use the formula:

Where

tn is the nth term [here we take the last one, 273

a is the first term [161]

d is the common difference [7]

and n is the number of terms, we are trying to find this.

Substituting we get:

Hence, there are 17 integers

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.