An optical inspection system is used to distinguish among different part types. the probability of a correct classification of any part is 0.96. suppose that three parts are inspected and that the classifications are independent. let the random variable x denote the number of parts that are correctly classified. determine the probability mass function of x. round your answers to four decimal places (e. g. 98.7654).

Probability Mass Function:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

Step-by-step explanation:

We are given the following information:

We treat correct classification  as a success.

P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

PMF:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

s + (a + 178) = 2000

step-by-step explanation:

2000 - 178 = 1822

1822 / 2 = 911

911 + 178 = 1089

1089 + 911 = 2000

abha = 1089

shane = 911

10000

step-by-step explanation: divide by 2,