Select the correct answer. and are tangent to circle c and circle f. the points of tangency are a, b, d, and e. if m∠dfe = 140°, what is m∠acb? a. 160° b. 140° c. 120° d. 110°

140°

Steps:

1) We know that, Sum of angles subtended at the centre and point of contact by tangents down from an external point is supplementary (180°).

=> /GFE + / DGE = 180°

=> 140° + /DGE = 180°

=> /DGE = 40°

3) Again Applying above Theorem,

=> /AGB + / ACB = 180°

=> 40° + /ACB = 180°

=> /ACB = 140° .

Hence, Angle ACB = 140°

step-by-step explanation:

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step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v