Could someone me with this question: a bag contains sweets of three different colours: orange, blue and yellow. 2/5 of the sweets are orange. there are 15 more blue sweets than yellow sweets.(a) how many blue sweets are there in the bag? (b) calculate the total number of sweets in the bag?

Yellow = x sweets

Blue = x + 15 sweets

Total number of sweets

Step-by-step explanation:

A bag contains sweets of three different colours: orange, blue and yellow. It is given that

Let x be the number of yellow sweets, then x + 15 is the number of blue sweets.

In total, there are x + x + 15 = 2x + 15 blue and yellow sweets.This number of sweets is exactly of all sweets, so there are

sweets in total.

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

ummm seems that u didnt post the attachement !