Mand n are two events p(m) = 0,60, p(n) = 0.20, and p (m and n) = 0.1.
find the probability of p(mor n).
p(92)
pm
mand n are inche ents
0.2
0.5
0.6
0.7

0.7

Step-by-step explanation:

This can be easily solved if we know the formula:

P(A or B) = P(A) + P(B) - P(A and B)

So, for this problem, we can modify the formula to be:

P(M or N) = P(M) + P(N) - P(M and N)

Using given information, we can solve:

P(M or N) = P(M) + P(N) - P(M and N)

P(M or N) = 0.6 + 0.2 - 0.1

P(M or N) = 0.7

Last answer choice is right, 0.7

can i see the following ?

step-by-step explanation:

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~