Apositive integer is twice another. thhe sum of the reciprocals of the positive integers is 3/10. find the two integers

Two required integers are 5 and 10.

Solution:

Given that a positive integer is twice another. The sum of the reciprocals of the positive integers is

We have to find the two integers.

Let assume that one integer = x

Since another integer is twice of first one, so second integer = 2x

Reciprocal of first integer =

Reciprocal of first integer =

Given that sum of reciprocal =

On solving above equation for x,

2x=10

x=5

First integer = x = 5

Second integer = 2x = 10

Hence two required integers are 5 and 10.

look a the sides they are perpendicular