Paul invested twice as much money in an account paying 4% interest
than he did in an account paying 3% interest. if the total interest paid
was $165, how much did he invest in each?
at 4% and $
at 3%

Step-by-step explanation:

Let x represent the amount invested at 3%. Then the amount invested at 4% is 2x, and the total interest is ...

  3%·x + 4%·2x = 165

  11%·x = 165 . . . . . . . . . simplify

  x = 165/0.11 = 1500

  2x = 3000

Paul invested $3000 at 4% and $1500 at 3%.

is there a picture

step-by-step explanation:

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1