Mathematics, 09.10.2019 04:00 potatocow

Relative and absolute change
in 2010 there were 1,845 students at ecc. in 2013 there were 2,430 students.
answer every answer as a positive number. round to the nearest 10th.

1. what is the absolute change in the student population at ecc over this period?
this is a:
student increase
or
student decrease

2. what is the relative change in the student population at ecc over this period?
% this is a:
(a) percent increase
or
(b) percent decrease

Answers: 3

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Answers

Answer from: ambert432

1. There was a 585 student increase over this period.

2. There was a 32% increase in the number of students during this period.

Step-by-step explanation:

1. What is the absolute change in the student population at ECC over this period?

To find the absolute change from 2010 to 2013, we subtract the number of students that there is in 2013 by the number of students that there were is 2010.

If the result is positive, there is a increase. If it is negative, it is a decrease.

In 2010 there were 1,845 students at ECC. In 2013 there were 2,430 students.

So, the absolute change is

2,430 - 1,845 = 585

There was a 585 student increase over this period.

2. What is the relative change in the student population at ECC over this period?

We can say that the number of students in 2010 is decimal 1, and solve a rule of three to find the decimal of the number of students in 2013. We then subtract the value found in the rule of three by one. If it is positive, there was a increase. If it is negative, there was a student decrease.

1,845 - 1

2,430 - x

1,845x = 2,430

$x = \frac{2,430}{1,845}$

x = 1.32

1.32 - 1 = 0.32

There was a 32% increase in the number of students during this period.

Answer from: Quest

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

Answer from: Quest

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

$\tan\left(x\right)=\frac{\left[altitude\right]}{\left[base\right]}=\frac{p}{r}$

$\tan\left(x\right)=\frac{p}{r}$

$\frac{p}{r}=tan(x)$

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).

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