Find four consecutive integers such that
twice the first subracted from the sum of
the other three integers is 16.

1st= 1

2nd =2

3rd =3

4th = 4

Step-by-step explanation:

Let's make an equation.

1) x

2) x+1

3) x+2

4) x+3

2*[(x+1+x+2+x+3)-x]=16

2*[(3x+6)]-x]=16

2[2x+6]=16

4x+12=16

4x=4

x=1

$25

step-by-step explanation:

25 - 4.50 = 20.5

20.5 / 2 = 10.25

10.25 + 10 = 20.25

20.25 - 12.50 = 7.75

therefore the answer is $25 as shown as the first number.