Acircular pool measures 88 feet across. one cubic yard of concrete is to be used to create a circular border of uniform width around the pool. if the border is to have a depth of 3 inches, how wide will the border be?

  4.667 inches

Step-by-step explanation:

The volume of the border is the product of its area and depth. Its area is the product of its width and the length of its centerline.

If x is the width of the border in feet, the diameter of its centerline is ...

  d = 88+x

Then the circumference of that circle, the length of the centerline, is ...

  C = πd = π(88+x)

and the area is the product of this length and the width of the border:

  A = xC = πx(88+x)

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The depth is expected to be 3 inches, or 1/4 foot, and the volume is (3 ft)³ = 27 ft³. So, we have the volume equation ...

  V = (1/4)A = 27

  πx(88+x)/4 = 27

  x^2 +88x = 108/π . . . . . multiply by 4/π

  x^2 +88x + 44^2 = 108/π +44^2 . . . . complete the square

  (x +44)^2 = (108/π) +1936 . . . . . . . . . .write the equation as a square

We want the solution that is near zero, so, taking the positive square root, we get ...

  x = -44 +√(108/π +1936) ≈ 0.388934 . . . . feet

The width in inches is 12 times this value, or about 4.667 inches.

the answer is 1/4

step-by-step explanation:

the rocket cannot penetrate the ground, in a contextual sense, therefore the roots of this equation should be the domain of this function. i'll let you find the roots of this quadratic equation (hint: use the quadratic formula:  

1- c

2-a

step-by-step explanation:

mark brainliest!