Use the given values of nequals=93 and pequals=0.24 to find the maximum value that is significantly low, muμminus−2sigmaσ, and the minimum value that is significantly high, muμplus+2sigmaσ. round your answer to the nearest hundredth unless otherwise noted.

The maximum value that is significantly low is 14.0828

The minimum value that is significantly high is 30.5572

Step-by-step explanation:

If we assume a binomial distribution, n is equal to 93 and p is equal to 0.24, the mean μ and the standard deviation σ are calculated as:

μ = n*p = 93*0.24 = 22.32

σ =

Then, the maximum value that is significantly low, μ−2σ, and the minimum value that is significantly high, μ+2σ, are equal to:

μ − 2σ = 22.32 - 2(4.1186) = 14.0828

μ + 2σ = 22.32 + 2(4.1186) = 30.5572

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.