Suppose that a, b, and c are three independent events such that pr(a) = 1/4, pr(b) = 1/3, and pr(c) = 1/2. (a) determine the probability that none of these three events will occur. (b) determine the probability that exactly one of these three events will occur.

a) 1/4

b) 11/24

Step-by-step explanation:

A, B, and C are three independent events.

Considering Pr(A'), Pr(B') and Pr(C') probabilities of not occoring A, B and C, so:

Pr(A) = 1/4 Pr(A') = 3/4

Pr(B) = 1/3 Pr(B') = 2/3

Pr(C) = 1/2 Pr(C') = 1/2

(a) Determine the probability that none of these three events will occur.

Pr(A') * Pr(B') * Pr(C') = 3/4 * 2/3 * 1/2 = 1/4

(b) Determine the probability that exactly one of these three events will occur.

exactly one means:

1) A occur B not occur and C not occur OR

2) A not occur B occur and C not occur OR

3) A not occur B not occur and C occur. So,

1) 1/4*2/3*1/2 = 1/12

2) 3/4*1/3*1/2 = 1/8

3) 3/4*2/3*1/2 = 1/4

1/12 + 1/8 + 1/4 = 11/24

not enough information

step-by-step explanation:

we cannot know this, because the other students could have handed out 10 flyers, or they could have handed out 100. one way, the mean would go up, and another way, the mean would go down.

answer: are you

step-by-step explanation: