Write the virtud for a parabola that satisfies the condition given. then write the equation in the form y=ax^2+bc+c. vertex (3,1) and a=3 write the equation in the form y=ax^2+bx+c

Step-by-step explanation:

For vertex (h, k) and vertical scale factor "a", the vertex form of the equation of a parabola is ...

  y = a(x -h)^2 +k

For (h, k) = (3, 1) and a = 3, the equation in vertex form is ...

  y = 3(x -3)^2 +1

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Expanding this gives the equation in standard form.

  y = 3(x^2 -6x +9) +1

  y = 3x^2 -18x +28

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

i believe that the slope of the line is -5

step-by-step explanation: