Agolfer hits his ball with speed v o at an angle 6 above the horizontal ground. assuming that the angle 0 is fixed and that air resistance can be neglected, what is the minimum speed v o (min) for which the ball will clear a wall of height h, a distanced away? your solution should get into trouble if the angle 0 is such that tan 0 < h 1 d. explain. what is v o (min) if 6 = 25°, d = 50 m, and h = 2 m?

The equation for the maximun height is given by the parametric equation of parabola

Step-by-step explanation:

We have that

with

getting the general equation

For sure if the tangent of theta is less than h/d the ball doesn´t pass through the wall, this because we have the following trigonometric relation

so if the tangent of theta is less than that fraction the ball won´t clear the wall.

Finally for those data we have:}

  or  

step-by-step explanation:

if the four friends split the cost, p, of the pizza evenly, then each friend pays one-fourth of the cost of the pizza.

the expression is   or  

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)