Write the point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of 1/4 include all of your work in your final answer.

The point-slope form of the line that passes through (5,5) and is perpendicular to a line with a slope of is 4x + y -25 = 0

Solution:

The point slope form of the line that passes through the points and perpendicular to the line with a slope of “m” is given as  

---- eqn 1

Where “m” is the slope of the line. are the points that passes through the line.

From question, given that slope “m” =

Given that the line passes through the points (5,5).Hence we get

By substituting the values in eqn 1 , we get the point slope form of the line which is perpendicular to the line having slope can be found out.

y - 5 = -4(x - 5)

y - 5 = -4x + 20

on simplifying the above equation, we get

y - 5 + 4x -20 = 0

4x + y - 25 = 0

hence the point slope form of given line is 4x + y - 25 = 0

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23