Answers should be exact decimals ( do not leave as fractions or unfinished calculations). a six-sided die (cube) with faces numbering 1,2,3,4,5,6 is loaded so that the probability of a six is 1/2. all the remaining numbers are equally likely.1) we roll the loaded die four times. find the probability ..all the rolls are 2: none of the rolls are 2: exactly one of the rolls is a 2: at least one of the rolls is a 2: either the first roll or the last roll is a 2:

(a) P = 0.0001

(b) P = 0.6561

(c) P = 0.2916

(d) P = 0.3439

(e) P = 0.2

Step-by-step explanation:

This is a probability problem.

The dice is rolled 4 times (n=4) and we calculate the probability of different outcomes.

The probability of a 6 in a roll is 0.5.

The probability of a 1, 2, 3, 4 or 5 in a roll is 0.5/5=0.1.

a) Outcome: all the rolls are 2.

The probability of having a 2 in a roll is 0.1, so we can calculate the probability of having a 2 in four consecutive rolls as

b) Outcome: none of the rolls is a 2.

The probability of having any other number but 2 in 4 rolls is:

c) Outcome: exactly one roll is a 2

This is the sum of the probability of having a 2 in the first, second, third or fouth roll, and others numbers in the rest of the rolls. These 4 combinations have the same probability, so we will multiply it by 4.

d) Outcome: at least one of the rolls is a 2

In this case, is the probability of having at least one 2, is the sum of the probability of getting a 2 in the first roll, the probability of getting a 2 in the second roll, the probability of getting a 2 in the third roll and the probability of getting a 2 in the four roll:

e) Outcome: either the first roll or the last roll is a 2

The probability of getting a 2 in the first roll is equal to having it in a fourth roll, and its the probability of getting a 2 in a roll (multiplied by 2, beacuse there can be either in the first or in the last roll).

1260=3*6*7*10=3^2*2^2*7*5 perfect cude = 3^3*2^

step-by-step explanation: