The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the plane of the equator. assuming the earth is a sphere with a radius of 6.38 x 106 m, determine the speed and centripetal acceleration of a person situated (a) at the equator and (b) at a latitude of 30.0° north of the equator.

a)

Speed at Equator = 463.97 meters per second

Centripetal Acceleration at Equator = meters per second squared

b)

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration at 30 degrees north of equator = meters per second squared

Step-by-step explanation:

The formula is:

Where

v is speed

R is radius

T is time

and another formula for centripetal acceleration:

Now,

a)

at equator, the radius is radius of earth (given), time in seconds is

T = 24 * 60 * 60 = 86,400

THus,

Speed at Equator = 463.97 meters per second

Centripetal Acceleration:

Centripetal Acceleration at Equator = meters per second squared

b)

At 30.0° north of the equator:

Now,

Speed =

Speed at 30 degrees north of equator = 401.79 meters per second

Centripetal Acceleration:

Centripetal Acceleration at 30 degrees north of equator = meters per second squared

10 miles

step-by-step explanation:

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3