Y= –a system of equations. y equals negative startfraction one-half endfraction x plus 4. x plus 2 y equals negative 8.x + 4
x + 2y = –8
how many solutions does this linear system have?

one solution: (8, 0)
one solution: (0, 8)
no solution
infinite number of solutions

Y = -1/2x + 4

X + 2y = -8

Replace y in the second equation with the first one:

X + 2(-1/2x +4)=-8

Simplify:

X -X +8 = -8

Simplify:

8 = -8

Subtract 8 from both sides:

0 = -16

This is a false statement, so there are no solutions.

a complex number is a number that can be expressed in the form a + bi, where a and b are real numbers, and i is a solution of the equation x2 = −1. because no real number satisfies this equation, i is called an imaginary number. has no real solution, since the square of a real number cannot be negative.