The equation shows a chemical reaction using 64 grams of calcium, 162 grams of zinc carbonate, and 152 grams of calcium carbonate.

calcium + zinc carbonate → calcium carbonate + zinc

according to the law of conservation of matter, how much zinc is present in the product?
group of answer choices

98 grams

64 grams

74 grams

88 grams

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question 64.5 pts
tim dissolves 0.5 grams (g) of sugar in a beaker containing 50.0 g of water, as shown below.

what is the mass of the solution?
group of answer choices

45.5 g

50.0 g

50.5 g

25.0 g

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question 74.5 pts
in her chemistry class, carmen performed an experiment that involved a chemical reaction. she measured the total mass of the reactants she used in her experiment using a triple-beam balance. the measurement she obtained is illustrated below.

image

according to the law of conservation of mass, what was the mass of the products in her experiment?
group of answer choices

342 g

240 g

243 g

300 g

Zn and ZnCO_3 occur in a 1:1 ratio in this reaction. Zn has a molar mass of about 65.38 g/mol; C has a molar mass of 12.011 g/mol; and O has a molar mass of 15.999 g/mol. So ZnCO_3 has a total molar mass of about 125.4 g/mol. In this reaction,

are involved, so that about 1.29 moles of Zn are produced, which has a mass of

(round up to 88 g)

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Masses add, so the total mass of the solution is 50.5 g

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Hard to answer without the image...

1. mass of Zn = 74 g

2. mass of solution = 0.5 + 50.0 = 50.5 g

3 mass of reactant = mass of the products

1.  

calcium + zinc carbonate → calcium carbonate + zinc

Ca + ZnCO₃ → CaCO₃ + Zn

calcium = 64 grams

zinc carbonate  = 162 grams

calcium carbonate = 152 grams

let the mass of zinc = x grams

Using the law of conservation of matter that states that matter is neither created nor destroyed. This law is known as law of indestructibility of matter. It simply implies the total mass of product is the same as the total mass of the reactant. Therefore,

64g  + 162g  = 152g + x

226 - 152 = x

x = 74g

mass of Zn = 74 g

2.

He dissolves 0.5 gram of sugar in a beaker containing 50.0 g of water. The mass of the solution can be calculated as follows:

mass of solution = 0.5 + 50.0 = 50.5 g

3.

Using the law of conservation of mass, the mass of the reactant should be equals to the mass of the products.

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step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.